Miguel Cabrera could win both the Triple Crown and the even more rare ‘Sextuple Crown’

Mike Oz

How many crowns can one man wear? If said man is Miguel Cabrera, the answer is "however many he pleases." But six would do in 2013.

As Ted Berg at For The Win points out Miggy is in contention not just for his second consecutive Triple Crown, but also the unofficial "Sextuple Crown." Both of these are ridiculous feats. No one has ever won two consecutive Triple Crowns. And only five other players have accomplished the "Sextuple Crown," which is just as sexy as its name suggests.

It is leading the league in the three Triple Crown statistics — homers, batting average and RBIs — and also hits, on-base percentage and slugging percentage. If there were a statistic measuring the baddest dude around with a baseball bat, Miggy'd win that too.

The other "Sextuple Crown" winners are Nap Lajoie, Ty Cobb, Rogers Hornsby, Chuck Klein and Carl Yastrzemski, each one of them a Hall of Famer. Yastrzemski is the last player to win achieve the Sextuple, which he did in 1967. Until Cabrera's 2012 campaign, that was the also the last Triple Crown in MLB.

So what does Miggy have to do to win both of these awards? His main obstacle is home runs. He trails Chris Davis of the Baltimore Orioles, 46-43. But Cabrera has hit 11 in August to Davis' eight, putting the AL home-run lead well within his reach. Miggy leads the AL (and all of baseball, actually) in the other five categories.

If we're looking at just the Triple Crown, Cabrera has a really good shot if he can catch Davis in homers. Barring injuries, of course. He is 12 RBIs ahead of Davis and 29 points better than Mike Trout in batting average.

The main takeaway here? Miguel Cabrera is so good we have to invent awards for him to win.

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