Lisicki, Bacsinszky in Luxembourg Open final

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LUXEMBOURG (AP)—Sabine Lisicki of Germany came back to defeat Shahar Peer of Israel 6-3, 4-6, 7-6 (5) on Saturday to advance to the Luxembourg Open final against Timea Bacsinszky of Switzerland.

The unseeded Bacsinszky upset fifth-seeded Yanina Wickmayer 3-6, 6-2, 7-5 in the early semifinal, ending the Belgian’s eight-match winning streak.

Bacsinszky had lost to Wickmayer last week in Linz, Austria, where Wickmayer won her second career WTA Tour title.

This time, the Swiss rallied from a set down and held on after blowing a 4-1 lead in the third set. Bacsinszky is playing for her first title in Sunday’s final.

The sixth-seeded Lisicki fought back from 4-2 down in the third set and 5-3 down in the tiebreaker.

Lisicki won her first career title at Charleston in April. She beat Bacsinszky in their only previous match in this year’s Fed Cup.

Updated Oct 24, 7:18 pm EDT
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3 Comments

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  1. Truthsayer
    3. Posted by Truthsayer Sun Oct 25 2:22am EDT

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    Lisicki with her wicked game.........interesting final.
  2. Scott J
    2. Posted by Scott J Sat Oct 24 12:56pm EDT

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    that's surprising. timea hasn't been in excellent form this season.
  3. Scott J
    1. Posted by Scott J Sat Oct 24 12:55pm EDT

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    that's surprising. timea hasn't been in excellent form this season.
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