Stephen Drew returns in Red Sox shuffle

David Brown
June 2, 2014
Toronto Blue Jays v Boston Red Sox
BOSTON, MA - MAY 21: Stephen Drew #7 of the Boston Red Sox leaves the field after batting practice before a game with the Toronto Blue Jays at Fenway Park on May 21, 2014 in Boston, Massachusetts. (Photo by Jim Rogash/Getty Images)

Stephen Drew returns to the Boston Red Sox on Monday night when they play the Cleveland Indians at Progressive Field. Drew signed with Boston on May 20 after spending more time on the free-agent market than either he or agent Scott Boras expected. He went 5 for 21 over 10 days regaining his timing at the plate during a minor league stint.

What does it mean for Xander Bogaerts? He's been taking ground balls at third in anticipation of Drew getting most of the playing time at shortstop going forward. He gave the right answer, if also a political one, when asked about moving back to third base. Via MassLive.com:

"Stephen's a great player," Bogaerts said. "I don't know when he'll be with us, but as soon as he comes, he's just an upgrade. I'm definitely looking forward to having him play beside me."

It's not ideal for Bogaerts' development, taking him off shortstop, but he's talented enough and, probably, mature enough that he'll be fine in the long run. And Drew playing short in the short run helps the Red Sox, who have won seven straight after beating Tampa Bay 4-0 on Sunday.

Brock Holt, who has been playing well at third base and went 4 for 4 against the Rays, will be moved to first base — for now. Mike Carp is heading for the disabled list because of a fractured right foot, and Mike Napoli has been sidelined already.

Daniel Nava is being promoted as well. Garin Cecchini, who went 1 for 2 in his major league debut, was sent back to Class AAA.

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David Brown is an editor for Big League Stew on Yahoo Sports. Have a tip? Email him at rdbrown@yahoo-inc.com and follow him on Twitter!

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